Description
Issue: Bug in get_position_from_periods
Function When Iteration Exceeds All Periods
Description
There is a potential bug in the get_position_from_periods
function within the CosineAnnealingRestartLR
class. The function is designed to return the index of the right-closest number in the cumulative period list based on the current iteration. However, if the iteration exceeds all values in the cumulative period list, the function does not handle this case properly, which can lead to unexpected behavior.
Code Snippet
def get_position_from_periods(iteration, cumulative_period):
"""Get the position from a period list.
It will return the index of the right-closest number in the period list.
For example, the cumulative_period = [100, 200, 300, 400],
if iteration == 50, return 0;
if iteration == 210, return 2;
if iteration == 300, return 2.
Args:
iteration (int): Current iteration.
cumulative_period (list[int]): Cumulative period list.
Returns:
int: The position of the right-closest number in the period list.
"""
for i, period in enumerate(cumulative_period):
if iteration <= period:
return i
return len(cumulative_period) - 1 # If iteration exceeds all periods, return the last period index
Problem
If the iteration
value exceeds all values in the cumulative_period
list, the function will not return any value within the loop, leading to potential issues in the learning rate scheduler.
Proposed Solution
To handle this case, we should ensure that the function returns the index of the last period if the iteration
exceeds all values in the cumulative_period
list. This can be achieved by adding a default return statement after the loop.
Suggested Fix
Add a default return statement to handle cases where the iteration exceeds all periods:
def get_position_from_periods(iteration, cumulative_period):
"""Get the position from a period list.
It will return the index of the right-closest number in the period list.
For example, the cumulative_period = [100, 200, 300, 400],
if iteration == 50, return 0;
if iteration == 210, return 2;
if iteration == 300, return 2.
Args:
iteration (int): Current iteration.
cumulative_period (list[int]): Cumulative period list.
Returns:
int: The position of the right-closest number in the period list.
"""
for i, period in enumerate(cumulative_period):
if iteration <= period:
return i
return len(cumulative_period) - 1 # If iteration exceeds all periods, return the last period index
Impact
This fix ensures that the function always returns a valid index, even when the iteration exceeds all values in the cumulative period list, preventing potential issues in the learning rate scheduler.