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Error on type inference inside an IF and arrow function when using --scrictNullChecks #19606

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@lmcarreiro

Description

@lmcarreiro

TypeScript Version: 2.7.0-dev.20171031

Code

declare function f(a: string, c: string): void;

function f2(a?: string, b?: string[]): void {
    if (a && b) {
        b.forEach( //b: string[]
            c => f(a, c) //a: string (OK)
        );
    }
}

function f3(a: string|undefined, b: string[]|undefined): void {
    if (a && b) {
        b.forEach( //b: string[]
            c => f(a, c) //a: string (OK)
        );
    }
}

function f4(x: any): void {
    let a: string|undefined = x.getA();
    let b: string[]|undefined = x.getB();
    if (a && b) {
        b.forEach( //b: string[]
            c => f(a, c) //a: string|undefined (should be just string)
        );
    }
}

function f5(x: any): void {
    let a: string|undefined = x.getA();
    let b: string[]|undefined = x.getB();
    if (a && b) {
        f(a, b[0]) //a: string (OK)
    }
}

function f6(x: any): void {
    let a: string|undefined = x.getA();
    let b: string[]|undefined = x.getB();
    if (a) {
        let d: string = a.toLowerCase();//a: string (OK)
        if (b) {
            b.forEach( //b: string[]
                c => f(a, c) //a: string|undefined (should be just string)
            );
        }
    }
}

Expected behavior:
No error, a: string|undefined should be string inside a if (a && b)

Actual behavior:
error TS2345: Argument of type 'string | undefined' is not assignable to parameter of type 'string'.
Type 'undefined' is not assignable to type 'string'.

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